(7)和差型の展開(解答) 学習日    月    日(   )
 乗法公式 5(和差型の展開)      (x+5)(x−5)
   =x2−52
   =x2−25
  (x+a)(x−a)=x2−a2 ← 平方の差 
   和 × 差
 
乗法公式を使って,次の式を展開しなさい。
1  (x+3)(x−3) = x2−9
 
2  (x+8)(x−8) = x2−64
 
3  (x+2)(x−2) = x2−4
  
4  (x−6)(x+6) = x2−36
  
5  (x−9)(x+9) = x2−81
  
6  (x+1)(x−1) = x2−1
  
7  (x+4)(x−4) = x2−16
 
8  (x−7)(x+7) = x2−49
 
9  (x+10)(x−10) = x2−100
  
10  (x−)(x+) = x2−
  
11  (3x+1)(3x−1) = 9x2−1
  
12  (2x−3)(2x+3) = 4x2−9
  
13  (x+5y)(x−5y) = x2−25y2
  
14  (a−2b)(a+2b) = a2−4b2
  
15  (4−3x)(4+3x) = 16−9x2
   (−9x2+16も可)
16  (9+x)(x−9) = (x+9)(x−9) 
  = x2−81 
17  (2x+9y)(2x−9y) = 4x2−81y2
 
18  (7x−3y)(7x+3y) = 49x2−9y2
 
19  (5a+3b)(5a−3b) = 25a2−9b2
  
20  (2x−)(2x+) = 4x2−
  

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