(2)多項式÷単項式(解答) 学習日    月    日(   )
 除法の分配法則
abc a b
c c
2で後ろから, 8x と −6y の順に割る
 (8x−6y)÷2= 8x 6y =4x−3y
2 2
 
分配法則を使って,次の式を展開しなさい。
 (8x+6)÷2 = 4x+3

 
 (3x−9)÷3 = x−3

 
 (6x+12y)÷3 = 2x+4y

 
 (25x−15y)÷5 = 5x−3y

 
 (12a+18b)÷6 = 2a+3b

  
 (4a−20b)÷4 = a−5b

  
 (27a−18)÷3 = 9a−6

  
 (6x−4)÷(−2) = −3x+2

  
 (x3x2x = x2x

 
10  (4y2−8y)÷2y = 2y−4

 
11  (8x2+28x)÷4x = 2x+7

  
12  (6x2−3x)÷(−3x) = −2x+1

  
13  (2x+8y+10)÷2 = x+4y+5

  
14  (9x2−12x−15)÷3 = 3x2−4x−5

  
15  (5x2+15xy−10x)÷5x = x+3y−2

  
16  (x2yxy2xy = xy

  
17  (3ax+9ay)÷3a = x+3y

  
18  (6xy+15y2−12y)÷(−3y)
  = 2x−5y+4
  
19
 (3a2ab a  = (3a2ab 2
a
  = 6a+2b  
20
 (2ab−10ab2 a =(2ab−10ab2 3
2a
  = 3b−15b2 
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