(10) かっこの式 (解答) | 学習日 月 日( ) | |
分配法則を使って,( )をはずす → 次に 同類項をまとめる 3(x+2)+2(x+3)=3x+6+2x+6=3x+2x+6+6=5x+12 |
1 | 2(x+4)+3(x+1) = 2x+8+3x+3 =5x+11 |
2 | 5(x+1)+4(x+2) = 5x+5+4x+8 =9x+13 |
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3 | 2(x−1)+3(x+2) = 2x−2+3x+6 =5x+4 |
4 | 3(2x+3)+2(x−4) = 6x+9+2x−8 =8x+1 |
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5 | 2(4x−3)+3(−x+2) = 8x−6−3x+6 =5x |
6 | 4(5x+2)−2(3x+2) = 20x+8−6x−4 =14x+4 |
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7 | 3(2x−5)−4(x−4) = 6x−15−4x+16 =2x+1 |
8 | 5(x−1)−2(−2x+1) = 5x−5+4x−2 =9x−7 |
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