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(7) 1次式の減法(解答) | 学習日 月 日( ) | |||
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1 | (5x+7)-(2x+3)=5x+7-2x-3 =5x-2x+7-3=3x+4 |
2 | (3x+4)-(x+1)=3x+4-x-1 =3x-x+4-1=2x+3 |
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3 | (8x+2)-(6x+1)=8x+2-6x-1 =8x-6x+2-1=2x+1 |
4 | (10x+5)-(7x+2)=10x+5-7x-2 =10x-7x+5-2=3x+3 |
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5 | (4x+2)-(3x+5)=4x+2-3x-5 =4x-3x+2-5=x-3 |
6 | (9x-1)-(8x+5)=9x-1-8x-5 =9x-8x-1-5=x-6 |
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7 | (4x-3)-(2x-6)=4x-3-2x+6 =4x-2x-3+6=2x+3 |
8 | (x+2)-(4x+2)=x+2-4x-2 =x-4x+2-2=-3x |
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9 | (5x-4)-(5x+2)=5x-4-5x-2 =5x-5x-4-2=-6 |
10 | (7x-1)-(2x-3)=7x-1-2x+3 =7x-2x-1+3=5x+2 |
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11 | (5y+1)-(y+9)=5y+1-y-9 =5y-y+1-9=4y-8 |
12 | (2a-6)-(4a+1)=2a-6-4a-1 =2a-4a-6-1=-2a-7 |
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13 | (2y-7)-5y=2y-7-5y =2y-5y-7=-3y-7 |
14 | (8-4a)-(a+6)=8-4a-a-6 =-4a-a+8-6=-5a+2 |
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15 | (-3x+9)-(3x-9)=-3x+9-3x+9 =-3x-3x+9+9=-6x+18 |
16 | (5y-3)-(-5y-3)=5y-3+5y+3 =5y+5y-3+3=10y |
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