(7) 1次式の減法(解答) | 学習日 月 日( ) | ||||
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1 | (5x+7)−(2x+3)=5x+7−2x−3 =5x−2x+7−3=3x+4 |
2 | (3x+4)−(x+1)=3x+4−x−1 =3x−x+4−1=2x+3 |
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3 | (8x+2)−(6x+1)=8x+2−6x−1 =8x−6x+2−1=2x+1 |
4 | (10x+5)−(7x+2)=10x+5−7x−2 =10x−7x+5−2=3x+3 |
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5 | (4x+2)−(3x+5)=4x+2−3x−5 =4x−3x+2−5=x−3 |
6 | (9x−1)−(8x+5)=9x−1−8x−5 =9x−8x−1−5=x−6 |
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7 | (4x−3)−(2x−6)=4x−3−2x+6 =4x−2x−3+6=2x+3 |
8 | (x+2)−(4x+2)=x+2−4x−2 =x−4x+2−2=−3x |
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9 | (5x−4)−(5x+2)=5x−4−5x−2 =5x−5x−4−2=−6 |
10 | (7x−1)−(2x−3)=7x−1−2x+3 =7x−2x−1+3=5x+2 |
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11 | (5y+1)−(y+9)=5y+1−y−9 =5y−y+1−9=4y−8 |
12 | (2a−6)−(4a+1)=2a−6−4a−1 =2a−4a−6−1=−2a−7 |
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13 | (2y−7)−5y=2y−7−5y =2y−5y−7=−3y−7 |
14 | (8−4a)−(a+6)=8−4a−a−6 =−4a−a+8−6=−5a+2 |
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15 | (−3x+9)−(3x−9)=−3x+9−3x+9 =−3x−3x+9+9=−6x+18 |
16 | (5y−3)−(−5y−3)=5y−3+5y+3 =5y+5y−3+3=10y |
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